help me with a math problem

Message Bookmarked
Bookmark Removed
Here's what I want to do: Determine how much rent I pay based on my salary in proportion to the salary of the person I live with. Currently we are splitting it equally but our incomes aren't equal.

A guy here at work just gave me this equation but I can't get it to work. Is the equation not quite right or am I just dumb at math? (I mean I know I'm dumb at math but I in this specific instance)

X = my monthly income
Y = other's monthly income

% = X/X+Y = Z (Z equals my percentage)

Z * total rent = my share

Miss Misery (thatgirl), Wednesday, 19 October 2005 16:38 (twenty years ago)

That makes no sense to me. Why X/X??

kelsey (kelstarry), Wednesday, 19 October 2005 16:40 (twenty years ago)

learn one order of operations

X/(X+Y)

Jonothong Williamsmang (ex machina), Wednesday, 19 October 2005 16:40 (twenty years ago)

xpost, but that answers your question too.

Jonothong Williamsmang (ex machina), Wednesday, 19 October 2005 16:41 (twenty years ago)

i wondered if we were missing the ().

kelsey (kelstarry), Wednesday, 19 October 2005 16:42 (twenty years ago)

make that "( )"

kelsey (kelstarry), Wednesday, 19 October 2005 16:43 (twenty years ago)

sorry. . .I couldn't type it the way he wrote it. He had X over X+Y. Look, I told you I'm dumb with math. I stopped with Algebra 2 and that was nearly 15 years ago!

Miss Misery (thatgirl), Wednesday, 19 October 2005 16:43 (twenty years ago)

right. so if x = $20,000 & y = $30,000 you come up with 4% & just for kicks, rent is $800, so 4% would be $320.

kelsey (kelstarry), Wednesday, 19 October 2005 16:44 (twenty years ago)

kelsey, what the fuck are you talking about

Paranoid Spice (ex machina), Wednesday, 19 October 2005 16:47 (twenty years ago)

4% !!??!!??

A Nairn (moretap), Wednesday, 19 October 2005 16:47 (twenty years ago)

40%. Sorry! I meant 40%!!!

kelsey (kelstarry), Wednesday, 19 October 2005 16:49 (twenty years ago)

I attack the very premise. What dif does it make? Rent is rent, it's not a sliding scale thing.

andy --, Wednesday, 19 October 2005 16:50 (twenty years ago)

If your roomate is also bad at math, here's a better equasion:

Z = X/X + Y/Y - XY/XY.
Roomate's share = (Total Rent) - Z

when something smacks of something (dave225.3), Wednesday, 19 October 2005 16:52 (twenty years ago)

Treat it objectively in this case Andy as the circumstances are personal and not important to the solution of the problem.

Miss Misery (thatgirl), Wednesday, 19 October 2005 16:52 (twenty years ago)

i don't know what miss misery's situation is, but i kinda wish my roomate & i would re-evaluate things. she's makes at least $8,000 more than I do & has the larger bedroom. My bedroom is a thumbnail & isn't heated during the winter.

kelsey (kelstarry), Wednesday, 19 October 2005 16:53 (twenty years ago)

thank you Kelsey b/c I think you helped me. This isn't exactly a 'roomate' situation so that's why I was trying to pose it more as a hypothetical situation.

Miss Misery (thatgirl), Wednesday, 19 October 2005 16:55 (twenty years ago)

it's just a word problem, in reality replace roommate with partner in crime, rent with loot and salary with number of hobos stabbed.

A Nairn (moretap), Wednesday, 19 October 2005 16:56 (twenty years ago)

I believe in progressive scales. Do some squaring or cubing or something!

Martin Skidmore (Martin Skidmore), Wednesday, 19 October 2005 16:59 (twenty years ago)

Divide your salary by his salary; you'll get a percentage (like .78). Instead of dividing the rent by 2, divide it by 1 + that percentage (1.78) in order to get his share. So if rent is 1200, he pays 675, and you pay 525 -- the same proportions as your respective salaries.

nabisco (nabisco), Wednesday, 19 October 2005 17:27 (twenty years ago)

Oh wait sorry no, you're not trying to figure out what the split would be, you're trying to figure out what the actual extra percentage rent burden is for you as opposed to him?

nabisco (nabisco), Wednesday, 19 October 2005 17:28 (twenty years ago)

Wait - do we know it's a him? It's a logical conclusion to draw from the facts so far, I'll admit, since who else would be willing to accept such a bargain?

If it is a him, a better formula would be: subtract your income from his, if the difference is greater than the rent, then he should pay it all.

o. nate (onate), Wednesday, 19 October 2005 17:34 (twenty years ago)

Dude! You're really stickin' it to the poor bastard!

nabisco (nabisco), Wednesday, 19 October 2005 17:38 (twenty years ago)

Well, I wouldn't pay that much, but maybe he's nicer than me. It's worth a shot anyway, and then when she lets him off with just paying a higher percentage, he'll feel grateful!

o. nate (onate), Wednesday, 19 October 2005 17:46 (twenty years ago)

so wait - now that you have the parens, its working fine, right?

petesmith (plsmith), Wednesday, 19 October 2005 17:47 (twenty years ago)

when you guys have this one figured out, I'm going to ask one involving compound interest okay?

teeny (teeny), Wednesday, 19 October 2005 17:53 (twenty years ago)

I like Nabisco's solution. How is it different than the first equation? My brain is very numb these days.

Miss Misery (thatgirl), Wednesday, 19 October 2005 18:06 (twenty years ago)

They're basically the same thing, S -- just figured there was a simpler way of putting it.

The original equation asks you to figure out what percentage of total household income you bring in: X/(X+Y) = your income divided by total you-and-him income. So if you make like 47% of total money, then you pay 47% of rent, or whatever else.

The way I put it is actually maybe more complicated -- figuring out what percent of his income you make, then arranging to pay that percent of what he pays for everything.

You're better off doing it the first way, so you can go around saying "listen, bub, I bring home 46.8% of the bacon in this house, and I say we're renting Tuck Everlasting."

nabisco (nabisco), Wednesday, 19 October 2005 18:14 (twenty years ago)

nabisco, im not sure yours makes sense. theoretically, MM's percent of roomie's rent should be the same as her percent of salary using the initial equation. im not sure why you'd divide by (1 + salary ratio).

petesmith (plsmith), Wednesday, 19 October 2005 18:17 (twenty years ago)

What's complicated about compound interest?

Forest Pines (ForestPines), Wednesday, 19 October 2005 18:20 (twenty years ago)

uh, nevermind. nabisco's is fine. but it doesnt really have anything to do with interest...

petesmith (plsmith), Wednesday, 19 October 2005 18:21 (twenty years ago)

no that was my question! and here it is:

I have two loans, one for 15000 at 5% over 3 years, and one for 40000 at 10% over 30 years. If I have money to pay more than my minimum payment, is it better to put it toward the second one because the interest rate is higher (and I would be eating away at the principal early in the life of the loan), or is it better to put it toward the first one because the minimum payment is higher, so once I get that one paid off, it frees up a good chunk of my budget?

I hope that made sense.

teeny (teeny), Wednesday, 19 October 2005 18:30 (twenty years ago)

Ha, P, I should show my work:

Let X = his adjusted rent share
X + .78X = RENT
1.78x = RENT
x = RENT/1.78

But I like the first one better, since it gives her a number that expresses her share of total income (and not just her earnings relative to his).

nabisco (nabisco), Wednesday, 19 October 2005 18:31 (twenty years ago)

xpost whoops Teeny sorry I just noticed something really important going down on that other thread, you know, over there ok bye

nabisco (nabisco), Wednesday, 19 October 2005 18:32 (twenty years ago)

it just took me a second to see that
(r1+r2)/(1+(s1/s2)) = (s2/(s1+s2))*(r1+r2)

but it all falls out really easy. dividing by 1+salary ratio makes sense because then youre dividing by the number of "large shares" being paid, which is 1.75 instead of 2, in the equal rent case.

petesmith (plsmith), Wednesday, 19 October 2005 18:33 (twenty years ago)

oh hahaha - i didnt even see yr question about interest, teeny. my fault!

petesmith (plsmith), Wednesday, 19 October 2005 18:34 (twenty years ago)

here, here. lemme make up for it. ask about interest.

petesmith (plsmith), Wednesday, 19 October 2005 18:34 (twenty years ago)

Teeny, my gut reaction is that if you put extra money towards paying off the second loan then you'll save more money in the long run. I haven't done any working out, though.

Forest Pines (ForestPines), Wednesday, 19 October 2005 18:36 (twenty years ago)

just saw the question (i am a retarded reader today) - im doing some figuring now.

petesmith (plsmith), Wednesday, 19 October 2005 18:42 (twenty years ago)

Teeny, paying off the higher interest, longer term loan will save you more money in the long run.

Jaq (Jaq), Wednesday, 19 October 2005 18:43 (twenty years ago)

yeah - thats absolutely right - just think of the amount of interest that you gain each year for each loan:

40000*(1+(.1/12))^12 >>>>> 15000*(1+(.05/12))^12

so anything you can do to keep that fast interest from piling up is much better.

petesmith (plsmith), Wednesday, 19 October 2005 18:58 (twenty years ago)

PUtting $100/month toward the higher interest loan saves ~$53,500 and shortens the term by 16.5 years.

Putting $100/month toward the lower interest loan saves ~$225 and shortens the term by .5 years.

To put actual numbers to it. The magic of compound interest.

Jaq (Jaq), Wednesday, 19 October 2005 19:01 (twenty years ago)

actually now that I look at it I realize that the payment for the higher interest loan is only about $50 less anyway, for some reason I was thinking it was like half as much as the other loan. never mind.

teeny (teeny), Wednesday, 19 October 2005 19:11 (twenty years ago)

xpost: I've just been trying to work it out myself, and worked out that putting an extra $100 towards the short-term loan would save 7 months and $250. However, the calculation I used to work that out produces nonsense results when applied to the second loan, so obviously I've done something wrong.

Forest Pines (ForestPines), Wednesday, 19 October 2005 19:34 (twenty years ago)

God damned communists. Maybe he shouldn't be punished for earning more?!?

paulhw (paulhw), Wednesday, 19 October 2005 20:33 (twenty years ago)

Forest Pines - I have all the equations in an engineering econ book at home, but I just googled up "accelerated loan repayment" and the internets gave me what I wanted.

Jaq (Jaq), Wednesday, 19 October 2005 21:18 (twenty years ago)

three years pass...

This is a question about using the Simplex method to solve linear programming problems (uhh.....caek?)

- - for anyone who could help but doesn't want to read the rest of this, just skip to the last paragraph, where I finally get around to asking my question - -

I skipped class all week in one of my courses, because we're going over linear programming and I arrogantly figured I'd know everything he was going to teach because I did a bunch of linear programming a few semesters ago. But I had never solved problems using the simplex method, which is apparently what he was teaching. Now I have a homework problem that I'm required to solve using simplex, and I have to show my beginning and final tableaux.

I spent a few hours reading tutorials and doing practice problems, and I understand the basics of it. Then I found this online tool that basically does the leg work for you. You put in the objective function and the constraints, and then it solves it for you, and lays out the steps it took to get there.


Tableau #1
b m cl pl s1 s2 s3 s4 p
1 1 1 1 1 0 0 0 0 650000
0 0 0 1 0 1 0 0 0 162500
1 0 0 -1 0 0 -1 0 0 1
0 1 0 -1 0 0 0 -1 0 1
-0.06 -0.07 -0.075 -0.095 0 0 0 0 1 0

Tableau #2
b m cl pl s1 s2 s3 s4 p
0 1 1 2 1 0 1 0 0 649999
0 0 0 1 0 1 0 0 0 162500
1 0 0 -1 0 0 -1 0 0 1
0 1 0 -1 0 0 0 -1 0 1
0 -0.07 -0.075 -0.155 0 0 -0.06 0 1 0.06

Tableau #3
b m cl pl s1 s2 s3 s4 p
0 0 1 3 1 0 1 1 0 649998
0 0 0 1 0 1 0 0 0 162500
1 0 0 -1 0 0 -1 0 0 1
0 1 0 -1 0 0 0 -1 0 1
0 0 -0.075 -0.225 0 0 -0.06 -0.07 1 0.13

Tableau #4
b m cl pl s1 s2 s3 s4 p
0 0 1 0 1 -3 1 1 0 162498
0 0 0 1 0 1 0 0 0 162500
1 0 0 0 0 1 -1 0 0 162501
0 1 0 0 0 1 0 -1 0 162501
0 0 -0.075 0 0 0.225 -0.06 -0.07 1 36562.6

Tableau #5
b m cl pl s1 s2 s3 s4 p
0 0 1 0 1 -3 1 1 0 162498
0 0 0 1 0 1 0 0 0 162500
1 0 0 0 0 1 -1 0 0 162501
0 1 0 0 0 1 0 -1 0 162501
0 0 0 0 0.075 0 0.015 0.005 1 48750

I follow the logic of each progression EXCEPT for the last one. How does the last row get adjusted like that without affecting the others?

I f'd up the word rear (Z S), Friday, 3 April 2009 21:19 (seventeen years ago)

Oh, nevermind, I've got it. For row5, it should be .075row1 + row5. I'm not sure why that seemed so wrong 5 minutes ago.

Disregard (shouldn't be too hard)

I f'd up the word rear (Z S), Friday, 3 April 2009 21:32 (seventeen years ago)

the only thing i know about math... is that you go on thundays!!!!!!!!!!!!!!!!!

rip dom passantino 3/5/09 never forget (max), Friday, 3 April 2009 21:33 (seventeen years ago)

one year passes...

Help!

I have been asked to calculate the percentage difference between the amount of time people spent on a website in week 1 (6 minutes 3 seconds) and week 2 (5 minutes 11 seconds).

I can't figure out how to figure it out. I am not smart. Thank you.

Becky Facelift, Monday, 17 May 2010 12:20 (sixteen years ago)

Or would it work if I converted everything to seconds, then did 363 - 311, divide that number by 311, then x it by 100?

Becky Facelift, Monday, 17 May 2010 12:22 (sixteen years ago)

That seems wrong.

Becky Facelift, Monday, 17 May 2010 12:23 (sixteen years ago)

363 is 100%
1% is 3.63
311 divided by 3.63 is 85.67

People spent 14% less time the second week.

StanM, Monday, 17 May 2010 12:35 (sixteen years ago)

Or, what you said, but you divide by 363 and then x 100.

StanM, Monday, 17 May 2010 12:37 (sixteen years ago)

Now calculate the difference between week 2 and 3 if the third week would be 363 again! (Hint: it's not 14%) :-)

StanM, Monday, 17 May 2010 12:41 (sixteen years ago)

Hmm... People would have spent 16.7% more time the third week?
(as in, 311 - 363, divided by 311, then x 100?)

Thank you for the help, by the way!

Becky Facelift, Monday, 17 May 2010 12:48 (sixteen years ago)

Yes, that's it! ( No problem :-) )

StanM, Monday, 17 May 2010 12:50 (sixteen years ago)

three months pass...

(for k = 0 to ∞) Why does 1 = ∑(.2^k)*Po = Po/(1-.2) ?

I dont understand how to get the last part: Po/(1-.2)
Po = P_0 or P subscript 0

you doesn't hasta call me johnson (CaptainLorax), Friday, 20 August 2010 21:31 (fifteen years ago)

hah nvm!, someone on yahoo answers actually did it for me:

For an infinite geometric series with common ratio r satifying |r| < 1, the sum is known.


Σ a r^k = a/(1-r)
k = 0

This is the result used to get that last line.


Σ Po (0.2)^k = Po/(1-0.2) = 5Po/4.
k = 0

If this sum is supposed to equal 1, then Po = 4/5.

you doesn't hasta call me johnson (CaptainLorax), Friday, 20 August 2010 21:32 (fifteen years ago)

Who are these people on Yahoo answers that do everyone's homework? Every time I googled something for o-chem back in the day, someone would have always posted the question direct from my o-chem book to Yahoo answers, and it would always have at least one thoughtful, accurate answer. Who answers strangers' o-chem problems for fun????

full of country goodness and green pea-ness (Abbbottt), Saturday, 21 August 2010 00:24 (fifteen years ago)

do they get paid? I remember the google answers dudes would get paid. or there would be a bounty.

? (dyao), Saturday, 21 August 2010 00:24 (fifteen years ago)

or maybe the helpful dudes treat it as a study tool, i.e. explaining it shores up their own understanding of the problem

? (dyao), Saturday, 21 August 2010 00:25 (fifteen years ago)

As far as I know, I mean the question-asker was always just throwing the question up, no offer of anything in return. SO I don't think answerers were getting paid. It was weird!

full of country goodness and green pea-ness (Abbbottt), Saturday, 21 August 2010 00:26 (fifteen years ago)

It was really helpful to me, though. I don't think I could have got through o-chem w/out the internet.

full of country goodness and green pea-ness (Abbbottt), Saturday, 21 August 2010 00:26 (fifteen years ago)

That's what All Experts is all about! You get $0. I suppose there's really no other reason that people wanting to help other people.

daavid, Saturday, 21 August 2010 00:31 (fifteen years ago)

CaptainLorax, I know you're question has been answered, but just out of curiosity what's P_0? Just a constant?

daavid, Saturday, 21 August 2010 00:34 (fifteen years ago)

yes

you doesn't hasta call me johnson (CaptainLorax), Wednesday, 25 August 2010 23:21 (fifteen years ago)

two months pass...

what is integer n where 90% of n = 6?

http://www.theargus.co.uk/news/quirkies/8453119.Bognor_dog_swallows_couple_s_pension_cash/

xtc ep, etc (xp) (ledge), Tuesday, 9 November 2010 12:21 (fifteen years ago)

That doesn't work the way you think it does.

Six twenty pound notes = £120.

Since they had at least 90% of the actual paper body of the six notes, they were able to exchange the pieces for new notes.

Wheal Dream, Tuesday, 9 November 2010 12:25 (fifteen years ago)

what is the law in the uk regarding damaged notes?

dayo, Tuesday, 9 November 2010 12:26 (fifteen years ago)

It would be funny, though, if you only got a percentage value of torn paper money.

"The corner is torn off this note, therefore it is only worth 90p"

Wheal Dream, Tuesday, 9 November 2010 12:26 (fifteen years ago)

Yeah that did occur to me. "He was able to piece together 90% of the notes" would have made things clearer.

xtc ep, etc (xp) (ledge), Tuesday, 9 November 2010 12:30 (fifteen years ago)

I envision this couple as being smack addicts.

amazing disorder (rip van wanko), Tuesday, 9 November 2010 12:31 (fifteen years ago)

Get 10 x £20 notes. Cut 10% off each of them. Stick all the bits together. Now you've got £220.

Harrison Buttwhistle (NickB), Tuesday, 9 November 2010 12:48 (fifteen years ago)

!

xtc ep, etc (xp) (ledge), Tuesday, 9 November 2010 12:55 (fifteen years ago)

Of course you'd need some sort of backstory like your dog had chewed it all up or something.

Harrison Buttwhistle (NickB), Tuesday, 9 November 2010 12:59 (fifteen years ago)

thank god it's not a meth problem

Zeno, Tuesday, 9 November 2010 13:42 (fifteen years ago)

one year passes...

Hi. I have a math problem.

I'm dealing with a Facebook Page with 14058 fans. Over the month of April, the page has grown 1.22%.
1. If the page continues to grow at its current rate, how many fans will it have by the end of Dec?
2. Also, what % growth each month would be needed in order to reach 50 000 fans by the end of Dec?
3. Is there a formula I can use to calculate this stuff?

Argh math makes me feel really stupid please help!!

salsa shark, Wednesday, 2 May 2012 15:24 (fourteen years ago)

it depends on whether that growth is continuous or monthly

iatee, Wednesday, 2 May 2012 15:26 (fourteen years ago)

if that's a monthly growth rate, you just need to multiply the number of fans by 1.0122 to get the next month. I'd do it in a spreadsheet for multiple months so you can just repeat the multiplication but using the previous month's figures.

kinder, Wednesday, 2 May 2012 15:31 (fourteen years ago)

1. 14058 * (1.0122^8)
2. 14058 * x^8 = 50000

silverfish, Wednesday, 2 May 2012 15:31 (fourteen years ago)

it seems to be monthly from the q tbh?

underleg aeroboots i have smithed (darraghmac), Wednesday, 2 May 2012 15:32 (fourteen years ago)

8 months of 1.22% increase = 1.0122^8 = about 10%, 15490 fans.

50000 / 14058 = 3.556

8th root of 3.556 = 1.17118 - 17% increase every month.

Andrew Farrell, Wednesday, 2 May 2012 15:32 (fourteen years ago)

I think what iatee's asking is, you've gained 2535 fans in April, which is also 1.22% of your previous total - are you more likely to keep gaining 2535 per month or 1.22% per month?

Andrew Farrell, Wednesday, 2 May 2012 15:38 (fourteen years ago)

So it's basically like the formula for compound interest? I did try that initially but my final number looked way off so I thought it was wrong! Turns out I just can't add...
I don't know the dif bwn monthly and continuous sorry, if it helps I have to do this report each month so maybe monthly is the interval to aim for.
Thanks for the responses.

salsa shark, Wednesday, 2 May 2012 15:41 (fourteen years ago)

xpost I would say 1.22% pm
(funnily enough the growth rate was 20.56% throughout march so this isn't going to be an exact science)

salsa shark, Wednesday, 2 May 2012 15:42 (fourteen years ago)

ten months pass...

http://www.slate.com/articles/health_and_science/science/2013/03/facebook_math_problem_why_pemdas_doesn_t_always_give_a_clear_answer.html

At first, I thought 1 was the obvious and only answer (we call it BEDMAS, not PEMDAS), but now I see the case for 9. "Implied multiplication by juxtaposition"--I like the sound of that.

clemenza, Wednesday, 13 March 2013 17:32 (thirteen years ago)

it's 9 the way i was taught. feel like really this is a notation issue, not a rules issue.

call all destroyer, Wednesday, 13 March 2013 17:42 (thirteen years ago)

^^^^^otm

brimstead, Wednesday, 13 March 2013 17:46 (thirteen years ago)

re: notation issue

brimstead, Wednesday, 13 March 2013 17:46 (thirteen years ago)

lol at this

flopson, Wednesday, 13 March 2013 17:48 (thirteen years ago)

CAD OTM

Darth Icky (DJP), Wednesday, 13 March 2013 17:48 (thirteen years ago)

lol @ u guys emphatically otm'ing some arithmetic

flopson, Wednesday, 13 March 2013 17:50 (thirteen years ago)

^^^^^otm

― brimstead, Wednesday, March 13, 2013 5:46 PM (16 minutes ago) Bookmark Flag Post Permalink

re: notation issue

― brimstead, Wednesday, March 13, 2013 5:46 PM (16 minutes ago) Bookmark Flag Post Permalink

brimstead, Wednesday, 13 March 2013 18:03 (thirteen years ago)

nerds!!

brimstead, Wednesday, 13 March 2013 18:05 (thirteen years ago)

here's a good one

20/5 = 4, obviously

but does that represent ... five groups of four, or four groups of five?

the late great, Wednesday, 13 March 2013 18:17 (thirteen years ago)

IMO that represents 5 groups of 4

Darth Icky (DJP), Wednesday, 13 March 2013 18:18 (thirteen years ago)

in other words, when we divide 20 by 5 are we seeing how many groups of five fit into the 20, or are we seeing how big the parts are when we divide 20 into five equal parts

the late great, Wednesday, 13 March 2013 18:19 (thirteen years ago)

I read it as 2 times 0 divided by 5

iatee, Wednesday, 13 March 2013 18:23 (thirteen years ago)

well you're just hopeless

the late great, Wednesday, 13 March 2013 18:24 (thirteen years ago)

again, it's ambiguous

brimstead, Wednesday, 13 March 2013 19:06 (thirteen years ago)

CAD OTM

― Darth Icky (DJP), Wednesday, March 13, 2013 1:48 PM (1 hour ago) Bookmark Flag Post Permalink

mark this as the time a cs dude otm'd an english major re: a math problem

call all destroyer, Wednesday, 13 March 2013 19:07 (thirteen years ago)

as the first asian to post itt I do not otm cad, thereby banishing him into the lost lands where he will be forced to wander forever

乒乓, Wednesday, 13 March 2013 19:11 (thirteen years ago)

back to my rightful place

call all destroyer, Wednesday, 13 March 2013 19:11 (thirteen years ago)

I think that where one way of notating something has a greater possibility for ambiguity than the other, the less ambiguous way should be preferred. In the above example, if you wanted to make clear that you were looking for the answer 9, you would notate it as (6 / 2)(1 + 2) (assume the / is the other division symbol, the slash has its own problems). So when I see it without the first set of parentheses, I assume the result is supposed to be "1" and not "9".

space phwoar (Hurting 2), Wednesday, 13 March 2013 19:15 (thirteen years ago)

who uses an obelus anyways

j., Wednesday, 13 March 2013 19:15 (thirteen years ago)

yeah that's my #1 issue with this thing

ciderpress, Wednesday, 13 March 2013 20:04 (thirteen years ago)

Hurting otm

poking pocong (Noodle Vague), Wednesday, 13 March 2013 21:42 (thirteen years ago)

j. otm

C: (crüt), Wednesday, 13 March 2013 21:55 (thirteen years ago)

if you typed this into a calculator, you would get 9. 9 is the answer.

C: (crüt), Wednesday, 13 March 2013 21:56 (thirteen years ago)

Thank god none of this has real life implications.

brimstead, Wednesday, 13 March 2013 21:56 (thirteen years ago)

calculators are invariably fucking shit tbh

poking pocong (Noodle Vague), Wednesday, 13 March 2013 21:57 (thirteen years ago)

what does that even mean

C: (crüt), Wednesday, 13 March 2013 21:58 (thirteen years ago)

you have to fuck about with brackets on most calculators to perform tasks that don't require brackets when written down

poking pocong (Noodle Vague), Wednesday, 13 March 2013 22:01 (thirteen years ago)

bidmas/bodmas being a better system than the inadequacies of calculator design imo

poking pocong (Noodle Vague), Wednesday, 13 March 2013 22:01 (thirteen years ago)

i don't really get why you would, like, assume the answer and work backwards based on the notation or whatever hurting is saying above

call all destroyer, Wednesday, 13 March 2013 22:02 (thirteen years ago)

I'm not assuming the answer, I'm assuming that the person who wrote the problem would want to write it in the clearest way possible so that I get the answer.

space phwoar (Hurting 2), Wednesday, 13 March 2013 22:07 (thirteen years ago)

that is the worst possible assumption one can make about a math problem, particularly one that is intended to make people on Facebook fight

Darth Icky (DJP), Wednesday, 13 March 2013 22:18 (thirteen years ago)

this math problem really makes u learn a lot about urself

C: (crüt), Wednesday, 13 March 2013 22:20 (thirteen years ago)

well, no, in general what hurting said is true. a lot of the times a word or symbol will have more than one definition & it's up to the reader to understand which, based on the context

flopson, Wednesday, 13 March 2013 22:23 (thirteen years ago)

(xp)

flopson, Wednesday, 13 March 2013 22:24 (thirteen years ago)

tbf, the article uses almost identical logic to mine to come to the opposite conclusion, so maybe it's just the way I was taught

space phwoar (Hurting 2), Wednesday, 13 March 2013 22:25 (thirteen years ago)

Left to Right

brimstead, Wednesday, 13 March 2013 22:28 (thirteen years ago)

i've got a math/logic problem for you guys

ok so there's an island with 100 green-eyed natives and 900 black-eyed natives. all natives adhere to a religion where if u ever know your own eye-colour, you have to commit ritual suicide. one day, an explorer shores up on the island and says "at least one person on this island has green eyes." by the end of the following day, every green-eyed person has killed themselves. why?

flopson, Wednesday, 13 March 2013 22:48 (thirteen years ago)

imperialism

C: (crüt), Wednesday, 13 March 2013 22:50 (thirteen years ago)

Left to Right

― brimstead, Wednesday, March 13, 2013 6:28 PM (29 minutes ago) Bookmark Flag Post Permalink

yeah this

call all destroyer, Wednesday, 13 March 2013 22:58 (thirteen years ago)

one year passes...

hey flopson is it because they looked at everyone on the island and counted 99 people with green eyes, whereas if you had black eyes you counted 100?

the late great, Thursday, 9 October 2014 07:15 (eleven years ago)

https://xkcd.com/solution.html

abanana, Thursday, 9 October 2014 07:22 (eleven years ago)

that ... does not seem to be the same problem

the late great, Thursday, 9 October 2014 07:27 (eleven years ago)

i just realized the problem with what i said is that if they knew how many had green eyes they could have figured it out before explorer showed up to announce one person on this island has green eyes

the late great, Thursday, 9 October 2014 07:30 (eleven years ago)

ok so if there's only one green-eyed person it would be immediate suicide, because they realize it's them ... if there's two green-eyed persons, the first sees the second and thinks: why haven't they committed suicide yet? oh, because there must be another green-eyed person. gadzooks! it's me!

and from there it's proof by induction.

the late great, Thursday, 9 October 2014 07:37 (eleven years ago)


You must be logged in to post. Please either login here, or if you are not registered, you may register here.