― Pete (Pete), Friday, 21 May 2004 09:53 (twenty-two years ago)
― ken c (ken c), Friday, 21 May 2004 09:56 (twenty-two years ago)
(mainly as my addled brane can no longer remember how to do median or mode any more...)
― CarsmileSteve (CarsmileSteve), Friday, 21 May 2004 09:57 (twenty-two years ago)
i am quite mean these days
― stevem (blueski), Friday, 21 May 2004 09:58 (twenty-two years ago)
mode = number that occurs most often or closest to that
― stevem (blueski), Friday, 21 May 2004 09:59 (twenty-two years ago)
n-n-n-n-n-n-n-n-n-n-n-n-nineteen
― Onimo (GerryNemo), Friday, 21 May 2004 10:07 (twenty-two years ago)
Mean = what you get by adding n values together and then dividing by n
The mean of (10,10,30,40,50) is 140/5 = 28
Median = the middle value in an ordered list of n values.
The median of (10,10,30,40,50) = 30
Mode = the most frequent value.
The mode of (10,10,30,40,50) = 10
― Ricardo (RickyT), Friday, 21 May 2004 10:07 (twenty-two years ago)
2 2 2 2 2 2 3 3 3 3 3 5 6 7 28| mode | ^ medianmean = (2 + 2 + 2 + 2+...+28 ) / 15 = 4.866666― ken c (ken c), Friday, 21 May 2004 10:08 (twenty-two years ago)
mean = (2 + 2 + 2 + 2+...+28 ) / 15 = 4.866666
― ken c (ken c), Friday, 21 May 2004 10:08 (twenty-two years ago)
― ken c (ken c), Friday, 21 May 2004 10:09 (twenty-two years ago)
― ken c (ken c), Friday, 21 May 2004 10:10 (twenty-two years ago)
― Ricardo (RickyT), Friday, 21 May 2004 10:10 (twenty-two years ago)
― N. (nickdastoor), Friday, 21 May 2004 10:11 (twenty-two years ago)
― jel -- (jel), Friday, 21 May 2004 15:01 (twenty-two years ago)
― mookieproof (mookieproof), Friday, 21 May 2004 15:09 (twenty-two years ago)
― MarkH (MarkH), Friday, 21 May 2004 18:57 (twenty-two years ago)
― hstencil (hstencil), Friday, 21 May 2004 18:58 (twenty-two years ago)
― MarkH (MarkH), Friday, 21 May 2004 19:00 (twenty-two years ago)
― hstencil (hstencil), Friday, 21 May 2004 19:05 (twenty-two years ago)
Am I right in thinking that there are some ranges of numbers for which there simply isn't a mode. If your dataset is 1 2 3 4 5 then no number is more frequent than any other so there's no mode, right?
― MarkH (MarkH), Friday, 21 May 2004 19:11 (twenty-two years ago)
― jaymc (jaymc), Friday, 21 May 2004 19:33 (twenty-two years ago)
― hstencil (hstencil), Friday, 21 May 2004 19:34 (twenty-two years ago)
― oops (Oops), Friday, 21 May 2004 19:36 (twenty-two years ago)
― Leeefuse 73 (Leee), Friday, 21 May 2004 19:53 (twenty-two years ago)
― hstencil (hstencil), Friday, 21 May 2004 19:54 (twenty-two years ago)